(x^2+2x+7)/(x^2+2x+3)=x^2+2x+4

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Solution for (x^2+2x+7)/(x^2+2x+3)=x^2+2x+4 equation: 



(x^2+2x+7)/(x^2+2x+3)=x^2+2x+4

We move all terms to the left:

(x^2+2x+7)/(x^2+2x+3)-(x^2+2x+4)=0



Domain of the equation: (x^2+2x+3)!=0

We move all terms containing x to the left, all other terms to the right

x^2+2x!=-3

x∈R



We get rid of parentheses

-x^2+(x^2+2x+7)/(x^2+2x+3)-2x-4=0

We multiply all the terms by the denominator


-x^2*(x^2+2x+3)+(x^2+2x+7)-2x*(x^2+2x+3)-4*(x^2+2x+3)=0

We multiply parentheses

-x^2*(x^2+2x+3)-2x^3-4x^2-4x^2+(x^2+2x+7)-6x-8x-12=0

We get rid of parentheses

-x^2*(x^2+2x+3)-2x^3-4x^2-4x^2+x^2+2x-6x-8x+7-12=0

We do not support expression: x^3

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